Test Quiz #1

Question 1 of 3

\[\begin{gather} f(x) = p(x) = \lambda e^{-\lambda x} \\ F(x) = P(X \le x) = 1 – e^{-\lambda x} \\[6pt] E[X] = \frac{1}{\lambda} \\ E[X^2] = \frac{2}{\lambda^2} \\ V[X] = \frac{1}{\lambda^2} \end{gather}\]

aq1

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aw2

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[latex syntax="display"]\\begin{aligned} f(x) &= p(x) = \\lambda e^{-\\lambda x} \\\\ F(x) &= P(X \\le x) = 1 – e^{-\\lambda x} \\\\[6pt] E[X] &= \\frac{1}{\\lambda} \\\\ E[X^2] &= \\frac{2}{\\lambda^2} \\\\ V[X] &= \\frac{1}{\\lambda^2} \\end{aligned}[/latex]

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\[
\begin{aligned}
f(x)&=p(x)=\lambda e^{-\lambda x},
&
F(x)&=P(X\leq x)=1-e^{-\lambda x}
\\[6pt]
E[X]&=\frac{1}{\lambda},
&
E[X^2]&=\frac{2}{\lambda^2},
&
V[X]&=\frac{1}{\lambda^2}
\end{aligned}
\]

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\[\\begin{aligned} f(x) &= p(x) = \\lambda e^{-\\lambda x} \\\\ F(x) &= P(X \\le x) = 1 – e^{-\\lambda x} \\\\[6pt] E[X] &= \\frac{1}{\\lambda} \\\\ E[X^2] &= \\frac{2}{\\lambda^2} \\\\ V[X] &= \\frac{1}{\\lambda^2} \\end{aligned}\]

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\(\int_{a}^{b} x^2 \,dx = \left. \frac{x^3}{3} \right|_{a}^{b} = \frac{b^3}{3} – \frac{a^3}{3}\)

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Question 2 of 3

qq2

as1

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as2

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ad3

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Question 3 of 3

tt1

ds

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ad

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Test Quiz #1

28DGTL 14/07/2026

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